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CUT command delimiter in reverse

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# 1  
Old 12-04-2010
CUT command delimiter in reverse
Hi,
I've a situation where,

Code:
 
a=xxx.yyy.zzz.txt
EXTN=`echo $a | cut -d . -f2`

Using the above code it delimites and will return "yyy.zzz.txt" to EXTN. But i need to get only the extension "txt". so as per the above code it delimits in the first "." itself. Can anyone help how to do this cut in
Quote:
reverse
so that i always get the "txt" as a result.

Thanks,
Vasanth.
# 2  
Old 12-04-2010
first, the command EXTN=`echo $a | cut -d . -f2` will return yyy

If you need get txt, thy this:

Code:
EXTN=`echo $a | cut -d . -f4`

or
Code:
EXTN=${a##*.}

# 3  
Old 12-04-2010
Code:
 
echo $a
xxx.yyy.zzz.txt
EXTN=$(echo $a | cut -d . -f 4)
echo "$EXTN"
txt

# 4  
Old 12-04-2010
Hi rdcwayx,

Thanks for you reply!
It works in both the way. But the 2nd one suits my situation well becuase somtime i can have only one .(dot) in my input or 2 or 3 .(dots) somtime. I'm little new... and i don't understand the below code Smilie

Quote:
EXTN=${a##*.}
It would be great if you can you explain me the above code.

Thanks,
Vasanth.
# 5  
Old 12-04-2010
It removes the greatest occurence of the pattern '*.' at the beginning of variable 'a'.
See all the parameter expansion posssibiities in : Bash Reference Manual
# 6  
Old 12-04-2010
Also, see POSIX version Shell Command Language to see what's possible in shells other than bash
# 7  
Old 12-04-2010
Thank You All for your guidance which was most helpful for me.
-Vasanth.
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