Simplify Bash Script Using "sed" Or "awk"


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# 1  
Simplify Bash Script Using "sed" Or "awk"

Input file:

PHP Code:
2 aux003.net3.com error12
6 awn0117
.net1.com error13
84 aux008 error14
29 aux001
.ha.ux.isd.com error12
209 aux002
.vm.ux.isd.com error34
21 alx0027
.vm.net2.com error12
227 dux001
.net5.com error123
22 us008
.dot.net2.com error121
13 us009
.net2.com error129 
Expected Output:
PHP Code:
2 aux003 error12
6 awn0117 error13
84 aux008 error14
29 aux001 error12
209 aux002 error34
21 alx0027 error12
227 dux001 error123
22 us008 error121
13 us009 error129 
For now i used this:
Code:
sed -e 's/.net[1-5].com//' -e 's/.ha.ux.isd.com//'

But its not applicable for all domains, i have to put new -e on each domain.
How do we simplyfy this, so i can remove all the FQDN and just remain the hostname?

Last edited by Scott; 12-02-2010 at 06:39 AM.. Reason: One more code tag
# 2  
Try:
Code:
sed 's/\.[^ \t]*//'

# 3  
try if this helps..
Code:
sed 's/\.[^ ]*//' inputfile > outfile

# 4  
wow, it works like charm:

PHP Code:
# sed 's/\.[^ ]*//' /tmp/testerr.out
2 aux003 error12
6 awn0117 error13
84 aux008 error14
29 aux001 error12
209 aux002 error34
21 alx0027 error12
227 dux001 error123
22 us008 error121
13 us009 error129 
Thanks a lot guys
# 5  
Code:
awk -F'[. ]' '{print $1,$2,$NF}' file

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