Shell Programming and Scripting

Hi,

I've a variable for example..

Code:

ACTIVATION_DATE=2010-11-11

(the date above is a result of a sql query and not hardcoded)

now there is another file (test_2.parm) where there are many variables predefined..

Code:

REG_CODE=111
ACT_DATE=2010-10-10
CAN_DATE=8888-31-12

Now I want to search for "ACT_DATE=" in test_2.parm and replace the date there with the date in "ACTIVATION_DATE".. something like tis..

Code:

REG_CODE=111
ACT_DATE=$ACTIVATION_DATE
CAN_DATE=8888-31-12

I tried with few awk n sed scripts but none worked.. Please help.

Thanks in advance,
RRVARMA

Code:

ACTIVATION_DATE=2010-11-11

awk -F= -v var="$ACTIVATION_DATE" '/ACT_DATE/{$2=var}1' OFS="=" test_2.parm > newfile

Or:

Code:

ACTIVATION_DATE=2010-11-11

sed 's/\(ACT_DATE=\).*/\1'"$ACTIVATION_DATE"'/' test_2.parm > newfile