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Help with simple RegEx on grep

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# 1  
Old 11-30-2010
Help with simple RegEx on grep
Hello,

I am trying to grep my log files for ORA errors, except ORA-00001.
I have tried:
grep 'ORA*!(-00001)' *.log
but it is not working.

Any help will be much appreciated.
Thank you.
# 2  
Old 11-30-2010
Try:
Code:
awk '/ORA/&&!/ORA-00001/' file

This User Gave Thanks to cabrao For This Post:
drbiloukos
# 3  
Old 11-30-2010
Code:
sed -n '/ORA-[0-9][0-9]*[^00001]/p'

This User Gave Thanks to ygemici For This Post:
drbiloukos
# 4  
Old 11-30-2010
@ygemici. That will not work ([^00001] is equivalent to [^01]):
Code:
$ echo ORA-00011 | sed -n '/ORA-[0-9][0-9]*[^00001]/p'
$

Try this:
Code:
sed '/ORA-00001/d;/ORA/!d' infile

This User Gave Thanks to Scrutinizer For This Post:
drbiloukos
# 5  
Old 11-30-2010
Quote:
Originally Posted by Scrutinizer
@ygemici. That will not work ([^00001] is equivalent to [^01]):
Code:
$ echo ORA-00011 | sed -n '/ORA-[0-9][0-9]*[^00001]/p'
$

Try this:
Code:
sed '/ORA-00001/d;/ORA/!d' infile

thanks friend Smilie i have written this urgently i have forgotten other conditions..
however if we only except `ORA-00001` we can use this
Code:
sed -n '/ORA-/{;/00001/!p;}' infile

regards
ygemici
This User Gave Thanks to ygemici For This Post:
drbiloukos
# 6  
Old 11-30-2010
Code:
grep 'ORA' *.log |grep -v "-00001"

This User Gave Thanks to rdcwayx For This Post:
drbiloukos
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