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Shell Programming and Scripting

The loop was executed $count times

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# 1  
Old 11-19-2010
The loop was executed $count times
Code:
#!/bin/sh
count=0
for i in 2 4 6
do
   echo "i is $i"
   count='expr $count + 1'
done
echo "The loop was executed $count times"

with these scripts
my output is :
i is 2
i is 4
i is 6
The loop was executed expr $count + 1 times

What should I do to get the value instead of 'expr $count + 1?

Thanks for willing to help..

Moderator's Comments:
Mod Comment You got a PM with a guide how to use a descriptive subject. You also got a PM how and when to use code tags.
Last edited by zaxxon; 11-19-2010 at 04:25 AM..
# 2  
Old 11-19-2010
Change
Code:
count='expr $count + 1'

to
Code:
count=$(expr $count + 1)

# 3  
Old 11-19-2010
Please use backquote ` instead of single quote ' at the code
Instead of
Code:
count='expr $count + 1'

It should be
Code:
count=`expr $count + 1`

Last edited by sanjaypraj; 11-19-2010 at 03:10 AM.. Reason: Missed to close the CODE
# 4  
Old 11-19-2010
count='expr $count + 1'

correct one is


Code:
 
count=`expr $count + 1`

# 5  
Old 11-19-2010
Why not use the shell built-in:
Code:
count=$((count+1))

# 6  
Old 11-19-2010
Quote:
Originally Posted by Scrutinizer
Why not use the shell built-in:
Code:
count=$((count+1))

Smilie which can be written
Code:
((count++))

# 7  
Old 11-19-2010
or
Code:
let count++

Smilie
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