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Shell Script to Retry and Exit


 
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# 1  
Old 11-18-2010
Shell Script to Retry and Exit

ok, so I'm trying to add a function to my local script that runs a command on a remote host. The reason why this is needed is that, there are other scripts that run different commands on the same remote host.

so the problem is that many times there are multiple scripts being run on the remote host, which then causes collisions and all the multiple scripts abort with a "Query Timed Out" message. All these scripts connect to port 1040 on the remote host...which is why i guess they time out.

i want to put something in my local script try to run to a command on the remote host three times. during those three times, if it doesn't run into any problems, the script should just break.

if anyone has a better idea than the below please let me know.

thanks

Code:
#!/bin/sh

x=3

while [ $x -le 4 ] ; do

response=`echo "external_cmd backup.sh" | nc -w 3 bogus.godaddy.com 1040`

if [ $? -eq 0 ] ; then

break

elif [ $? -ne 0 ] ; then

response=`echo "external_cmd backup.sh" | nc -w 3 bogus.godaddy.com 1040`

fi

done

this is a nagios script by the way.
# 2  
Old 11-18-2010
If you need to run the script with the old Bourne shell:

Code:
counter=0 limit=3
while [ "$counter" -lt "$limit" ]; do
  response=`echo "external_cmd backup.sh" | nc -w 3 bogus.godaddy.com 1040` &&
    break
  counter=`expr $counter + 1`
done

With POSIX compliant shell you could use something more efficient:

Code:
counter=0 limit=3
while [ "$counter" -lt "$limit" ]; do
  response="$( 
    echo "external_cmd backup.sh" | 
      nc -w 3 bogus.godaddy.com 1040 
      )" &&
    break
  counter="$(( $counter + 1 ))"
done

zsh and recent versions of ksh93 and bash support a modern syntax like this:

Code:
counter=0 limit=3
while (( (( counter++ )) < $limit )); do
  response="$( 
    nc -w 3 bogus.godaddy.com 1040 <<< 'external_cmd backup.sh' 
    )" &&
    break
done


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