Breaking a column's value into multiple rows

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# 1  
Old 11-09-2010
Breaking a column's value into multiple rows

Hello Friends,

I am trying to implement the following using UNIX. I am getting a sequential file as input which would have two columns, "Name" and "Countries Visited". The "Countries Visisted" field will be multi-valued, each value separated by a space and also the number of values are not fixed. The file is tab delimited.
For example,
Name Countries Visited
My intended output is this:
Name Countries Visited
How can I use UNIX Shell Scripting to do this?
Many Thanks!!

# 2  
Old 11-09-2010
Easy solution in awk:

#!/usr/bin/env ksh
awk '
        NF > 1 {
                for( i = 2; i <= NF; i++ )
                        printf( "%s %s\n", $1, $(i) );
' <input_file

Strictly using shell commands:
while read name list
    for c in $list
        echo "$name $c"
done <input file

This User Gave Thanks to agama For This Post:
# 3  
Old 11-09-2010
awk 'NR==1{print;next} {for (i=2;i<=NF;i++)print $1,$i}' infile

This User Gave Thanks to rdcwayx For This Post:
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