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Format of SED command to change a date

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# 1  
Old 11-07-2010
Format of SED command to change a date
I have a website. I have a directory within it with over a hundred .html files. I need to change a date within every file. I don't have an easy way to find/replace.

I need to change 10/31 to 11/30 on every single page at once. I tried the command below but it didn't work. Obviously I don't know what I'm doing so any help would be appreciated.
Code:
/home/public_html/content$ sed '"10/31"/"11/30"'/g *

Last edited by Scott; 11-07-2010 at 06:05 AM..
# 2  
Old 11-07-2010
Try:
Code:
for f in *; do
  cp -p "$f" "$f.old" && sed 's|10/31|11/30|g' "$f.old" > "$f"
done

or GNU:
Code:
sed -i.old 's|10/31|11/30|g' *

This User Gave Thanks to Scrutinizer For This Post:
ijustsawmars
# 3  
Old 11-07-2010
Code:
find directory -type f -name "*.html" -exe sed -i.old 's|10/31|11/30|g'  {} \;

If your sed don't support -i option, replace by perl

Code:
find directory -type f -name "*.html" -exec perl -p -i.old -e 's|10/31|11/30|g'  {} \;

This User Gave Thanks to rdcwayx For This Post:
ijustsawmars
# 4  
Old 11-07-2010
Quote:
Originally Posted by Scrutinizer
Try:
Code:
for f in *; do
  cp -p "$f" "$f.old" && sed 's|10/31|11/30|g' "$f.old" > "$f"
done

Thanks for everyone's reply. The first one worked, so I just went with that. I will just run that once a month to change the date.
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