Login or Register to Ask a Question and Join Our Community


Shell Programming and Scripting

Regular expression (sed)

Login to Discuss or Reply to this Discussion in Our Community

 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting Regular expression (sed)
# 8  
Old 10-20-2010
Quote:
Originally Posted by agama
Assuming one --xxx per line, and that there might be text following the quoted string, this will work:

Code:
 sed -r 's/.*--xxx[^"]*"//; s/".*//'

I works

Thank all for comments
# 9  
Old 10-20-2010
using Perl:-

Code:
perl -wlne 'printf "$1 " while (s/\"(.*?)\"//);' infile.txt

SmilieSmilieSmilie
This User Gave Thanks to ahmad.diab For This Post:
blito_loco
# 10  
Old 10-20-2010
Regular expression (sed)
Quote:
Originally Posted by Scrutinizer
Code:
sed 's/[^"]*"\([^"]*\)"[^"]*/\1 /g' infile

Could you please explain your code?Smilie
# 11  
Old 10-20-2010
It looks for 0 or more characters-that-are-not-a-double-quote in front of a double quote. The zero or more characters-that-are-not-a-double-quote that follow are in parentheses, so they are group 1. All this has to be followed by a double quote and 0 or more characters-that-are-not-a-double-quote. If there is a match It replaces all this with what was stored in group 1 followed by a single space. It repeats for every such pattern on the line (g flag).
This User Gave Thanks to Scrutinizer For This Post:
Kesavan
# 12  
Old 10-21-2010
MySQL
Quote:
Originally Posted by Scrutinizer
It looks for 0 or more characters-that-are-not-a-double-quote in front of a double quote. The zero or more characters-that-are-not-a-double-quote that follow are in parentheses, so they are group 1. All this has to be followed by a double quote and 0 or more characters-that-are-not-a-double-quote. If there is a match It replaces all this with what was stored in group 1 followed by a single space. It repeats for every such pattern on the line (g flag).
Thank you Smilie
# 13  
Old 10-21-2010
Perl version of the same thing:
Code:
perl -pe 's/.*?"(.*?)".*?/\1 /g'

This User Gave Thanks to Scrutinizer For This Post:
blito_loco
Login or Register to Ask a Question

Previous Thread | Next Thread

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

sed regular expression

Hi , I need to remove pipe character from a |^ delimeted file. Something like |^tran|sformers||^|revenge |of fallen|^ to |^transformers|^revenge of fallen|^... Cold anybody please help to build the regular expression using sed . many thanks. Please use code tags next time for... (1 Reply)
Discussion started by: kokjek
1 Replies

2. Shell Programming and Scripting

I am learning regular expression in sed,Please help me understand the use curly bracket in sed,

I am learning SED and just following the shell scripting book, i have trouble understanding the grep and sed statement, Question : 1 __________ /opt/oracle/work/antony>cat teledir.txt jai sharma 25853670 chanchal singhvi 9831545629 anil aggarwal 9830263298 shyam saksena 23217847 lalit... (7 Replies)
Discussion started by: Antony Ankrose
7 Replies

3. UNIX for Advanced & Expert Users

sed: -e expression #1, char 0: no previous regular expression

Hello All, I'm trying to extract the lines between two consecutive elements of an array from a file. My array looks like: problem_arr=(PRS111 PRS213 PRS234) j=0 while } ] do k=`expr $j + 1` sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt ---some operation goes... (11 Replies)
Discussion started by: InduInduIndu
11 Replies

4. Shell Programming and Scripting

Help with sed regular expression

Hi all, I want to get a substring from a string based on given delimiter, for example: str="foo|bar|baz" with delimiter "|", I want to get one substring at each time with the order number the substring in the whole string, given 1 to get "foo", given 2 to get "bar", given 3 to get "baz", I... (2 Replies)
Discussion started by: Roy987
2 Replies

5. Programming

Perl: How to read from a file, do regular expression and then replace the found regular expression

Hi all, How am I read a file, find the match regular expression and overwrite to the same files. open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat"; open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat"; while (<DESTINATION_FILE>) { # print... (1 Reply)
Discussion started by: jessy83
1 Replies

6. UNIX for Dummies Questions & Answers

Regular Expression In Sed

Hi , I am learing sed echo abc 123 def 456 | sed 's|\(*\) \(*\)|\1|' is returning abc def 456 i was hoping abc def "\1" should only print the occurence of the first pattern but according to my understanding it is just removing the first occurence of the second pattern... (7 Replies)
Discussion started by: max_hammer
7 Replies

7. Shell Programming and Scripting

sed regular expression help

please consider this: echo "11111*X*005010X279~ST*270*1111111*005010X279~BHT*0011*11" | sed 's/.*\(005010X(\d)(\d)(\d)*\).*$/\1/'i'm searching for first occurrence of 005010X while leaving rest of characters out. :confused: any tips? thnx in advance guys. (7 Replies)
Discussion started by: grep01
7 Replies

8. Shell Programming and Scripting

Regular expression with SED

Hi! I'm trying to write a regexp but I have no luck... I have a string like this: param1=sometext&param2=hello&param3=bye Also, the string can be simply: param2=hello I want to return the value of param2: "hello". How can I do this? Thanks. (3 Replies)
Discussion started by: GagleKas
3 Replies

9. Shell Programming and Scripting

Regular expression with sed

Hi, I'm trying following:echo "test line XA24433 test" | sed 's/.*X\(.*\)/X\1/' XA24433 test While I want the output as: XA24433 I want to grab the words starting with letter X till the next space, this word can be anywhere in the line. (9 Replies)
Discussion started by: nervous
9 Replies
Login or Register to Ask a Question