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Date variable in shell script

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# 1  
Old 10-18-2010
Date variable in shell script
Hello guys n girls,

I am using ksh script on AIX platform.
I am getting a DATE from input file in "YYYYMMDDHHMISS" format.
Now I want the same date in "YYYYMMDD" format into another variable.

For example,
if the DATE is 20101018121445
then I need 20101018 in another variable.

Please let me know the command to do it.
Thanks in advance.
# 2  
Old 10-18-2010
On solaris on command line below date command gives 20101018, on AIX you can check the manual page of date cmd.
Code:
date '+%Y%m%d'

# 3  
Old 10-18-2010
Code:
$ DATE=20101018121445
$ DATE2=`echo $DATE | cut -c1-8`
$ echo $DATE2
20101018

This User Gave Thanks to cabrao For This Post:
Poonamol
# 4  
Old 10-18-2010
Something like this,

Code:
new_dt=$(echo "20101018121445" | cut -c1-8);echo $new_dt

# 5  
Old 10-18-2010
Code:
DATE=`date +%Y%m%d%H%M`
NEW_DATE=`echo ${DATE:0:8}`

# 6  
Old 10-18-2010
Quote:
Originally Posted by Poonamol
I am getting a DATE from input file in "YYYYMMDDHHMISS" format.
Now I want the same date in "YYYYMMDD" format into another variablee.

For example,
if the DATE is 20101018121445
then I need 20101018 in another variable.

This will work in any POSIX shell:
Code:
date=20101018121445
yyyymmdd=${date%??????} ## remove the last six characters

In bash and ksh93 you can do:
Code:
yyyymmdd=${date:0:8}

# 7  
Old 10-19-2010
Thank you so much for your time and reply.
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