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Elapsed time in seconds in awk

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# 1  
Old 10-07-2010
Tools Elapsed time in seconds in awk
I am trying to get the ellapsed time in seconds in the body of the awk script. I use unix date to get the time. It works in BEGIN {} but not in the body {} of awk. Any ideas?

Code:
$ cat a
BEGIN {
  "date +%s" | getline x
  print x
}
{
  "date +%s" | getline y
  print y
}
$ echo "one line" | awk -f a
1286442885

$

Last edited by Scott; 10-07-2010 at 08:58 AM.. Reason: Please use code tags
# 2  
Old 10-07-2010
in awk, if you need run shell command:

Code:
system("date +%s")

# 3  
Old 10-07-2010
does the system command allow to capture the output of it? Eventually I would like to subtract the values: y-x in the script. This script, obviously, does not work:

Code:
BEGIN {
  system("date +%s") | getline x
  print x
}
{
  system("date +%s") | getline y
  print y
}

Last edited by Scott; 10-07-2010 at 08:58 AM.. Reason: Code tags
# 4  
Old 10-07-2010
Ok, use systime function in awk.
Code:
cat a

BEGIN {
print systime()
}
{
print systime()
}

This User Gave Thanks to rdcwayx For This Post:
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