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Variable comparison in 'if' with a string.

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# 1  
Old 10-04-2010
Question Variable comparison in 'if' with a string.
Hi All,

I want to compare the variable value with string in a shell script.
my code is:
Code:
for var in $packsName
do 
 if [ $var -ne 'ABC' || $var -ne 'XYZ' ]
 then
   echo $var
 fi
done

But I am getting error as:
Code:
ABC : not found.

Am I going wrong somwhere?
please guide.

Thanks.
Last edited by Franklin52; 10-04-2010 at 05:39 AM.. Reason: Please use code tags!
# 2  
Old 10-04-2010
Code:
for var in $packsName
do 
if [ "$var" != "ABC" -o "$var" != "XYZ" ]
then
echo $var
fi
done

But I don't know if this test is really what you want to have, as it will always return true Smilie
# 3  
Old 10-04-2010
What I want is, in all the values for $var, I dont want the statements to be executed for ABC and XYZ.

I tried your solution, but it still prints for ABC and XYZ.
I dont want it to be printed.. Smilie
# 4  
Old 10-04-2010
Try:
Code:
for var in $packsName
do 
  if [ "$var" != "ABC" -a "$var" != "XYZ" ]
  then
    echo $var
  fi
done

# 5  
Old 10-04-2010
Thanks, -a option worked.

Can you please tell me the difference between -o and -a option?
# 6  
Old 10-04-2010
Quote:
Originally Posted by AB10
Thanks, -a option worked.

Can you please tell me the difference between -o and -a option?
-o means logical OR, while -a is logical AND.
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