How to use IFS in this scenario?


 
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# 1  
Old 10-02-2010
How to use IFS in this scenario?

Given the scenario like this, if at all if have to use IFS on the below given example, how it should be used.

IFS=/

eg:

Code:
 
/xyz/123/348/file1

I want to use the last slash /file1 . So can anyone, suggest me how to pick the last "/" as a IFS.
# 2  
Old 10-02-2010
try this,

Code:
echo '/xyz/123/348/file1' | awk -F/ '{print FS$NF}'

# 3  
Old 10-02-2010
Code:
echo '/xyz/123/348/file1' |  sed 's;.*/;/;'

# 4  
Old 10-02-2010
Hi, you do not need to use IFS for that, not an external program
Code:
$ file=/xyz/123/348/file1
$ echo ${file##*/}
file1
$ echo ${file%/*}
/xyz/123/348

# 5  
Old 10-02-2010
How about basename - that is designed to return the file name from a path. It will optionally remove suffixes (like file extensions)

Code:
>f=path/to/mydirectory/file.c
>basename $f
file.c
>basename $f .c
file

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