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Replace a var in sql file with shell script variable

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# 1  
Old 09-29-2010
Replace a var in sql file with shell script variable

I have a requirement where i have a sql file (filetext.sql). This file contains a variable ss_code.
Now in a shell script im trying to replace the variable ss_code with a value contained in the shell script variable MTK_DC..tried the below in the script

OUT=`awk -v ss_code=$MTK_DC '{print}' filetext.sql` # prints as such the sql file .. without replacing the variable

OUT=`awk -v bb_code=$MTK_DC '{gsub(ss_code, "bb_code")}1' filetext.sql` # this gives undesired output

Kindly throw some light..

Pls note:sql file and the shell script file are two different files present in the same location
# 2  
Old 09-29-2010
Post the sql file and the desired ouput.
# 3  
Old 09-29-2010
This is my sql file:
select cr.dol,cr.unit from cardb cr
where cr.frm in (ss_code)
after running the below script

OUT=`awk -v bb_code=$MTK_DC '{gsub(ss_code, "bb_code")}1' filetext.sql` # this gives undesired output

the sql file should change to
select cr.dol,cr.unit from cardb cr
where cr.frm in ('mit','cit','bit')
i have tried and got the desired o/p by changing the script as below. Pls tell me if the same could be got thru sed command
OUT=`awk -v bb_code=$MTK_DC '{gsub("ss_code", bb_code)}1' filetext.sql` # this gives undesired output

# 4  
Old 10-01-2010
Try this:
awk -v var=$MTK_DC '/ss_code/{sub("ss_code", var)}1' filetext.sql

# 5  
Old 10-01-2010
Thanks.. it worked out..

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