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Get the substring

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# 1  
Old 09-06-2010
Get the substring
Hi All,

I have a ouput string likes 'u8wos' or 'u10acsd' or somthing else 'u{number}{any characters}'and I want to get the number behind the letter 'u' by bash shell.



Thanks
Damon
# 2  
Old 09-06-2010
If there is only this constellation, ie. not more numbers at other positions and not other characters than alphanumerics, you can just delete all letters for example:
Code:
$> echo 'u8wos'| tr -d "[a-z]"
8

# 3  
Old 09-06-2010
same behaviour as above
Code:
for S in u8wos u10acsd
do
   echo "S='${S//[a-z]/}'"
done

if something different comes before the 'u' and/or after the numbers
Code:
for S in u8wos u10acsd
do
   S=${S#*u}
   echo "S='${S%%[a-z]*}'"
done

# 4  
Old 09-06-2010
Code:
sed -n 's/u//;s/[0-9]\+/&u/;p'

Last edited by john1212; 09-06-2010 at 01:08 PM..
# 5  
Old 09-06-2010
Code:
sed 's/u\([0-9]*\).*/\1/' infile

# 6  
Old 09-07-2010
Quote:
Originally Posted by rdcwayx
Code:
sed 's/u\([0-9]*\).*/\1/' infile

infile:
Code:
u123abecadlo
u234abecadl
u345abecad
u01mini

Code:
sed 's/u\([0-9]*\).*/\1/' infile

Code:
123
234
345
01

my
Code:
sed -n 's/u//;s/[0-9]\+/&u/;p' infile

result:
Code:
123uabecadlo
234abecadl
345uabecad
01umini

# 7  
Old 09-07-2010
Yes, mine is right. Thank you to prove it.

Request is:

Code:
get the number behind the letter 'u' by bash shell.

Only numbers.
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