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# 1  
Old 09-05-2010
Question on awk for finding the column number using a match word
Hi Guys,

Please help me out in my situation of writing a shell script

Exampl:I have a output like

Code:
asnapply 1 2 3 apply_server=1 apply_schema=ASN
asnapply 1 2 3 apply_server=2 apply_schema=ASN

Now i need output like
Code:
asnacmd applysever=1 applyschema=ASN stop
asnacmd applysever=2 applyschema=ASN stop

I tried awk but hardcoded and printed but i have a question instead of hardcoding the column number,how can i get the column number matching apply_server from input and print apply_server=1

Any help appreciated
Thanks
Last edited by Scott; 09-08-2010 at 07:12 PM.. Reason: Please use code tags
# 2  
Old 09-05-2010
Using the syntax $(i) will allow you to access a column using the contents of a variable, in this case 'i'.

Code:
#!/usr/bin/env ksh
awk -v col=${1:-1} ' {print $(col)}'

This example accepts a column number from the command line and prints just that column from stdin. If no column number is given, it defaults to the first column.
This User Gave Thanks to agama For This Post:
mallak
# 3  
Old 09-05-2010
Code:
awk '{gsub(/_/,"",$5);gsub(/_/,"",$6);print $1,$5,$6,"stop"}' infile

or something like:


Code:
awk '{$5="applysever=" NR;gsub(/_/,"",$6);print $1,$5,$6,"stop"}' infile

# 4  
Old 09-05-2010
Quote:
Originally Posted by agama
Using the syntax $(i) will allow you to access a column using the contents of a variable, in this case 'i'.

Code:
#!/usr/bin/env ksh
awk -v col=${1:-1} ' {print $(col)}'

This example accepts a column number from the command line and prints just that column from stdin. If no column number is given, it defaults to the first column.
Thanks for the quick reply

Code:
awk '{$5="applysever=" NR;gsub(/_/,"",$6);print $1,$5,$6,"stop"}' infile

That was the problem for Me i cannot say $5 to applyserver, becoz it can be any where.

My awk command shuld search where applyserver is and return me the value of the column

---------- Post updated at 09:32 PM ---------- Previous update was at 09:28 PM ----------
Quote:
Originally Posted by agama
Using the syntax $(i) will allow you to access a column using the contents of a variable, in this case 'i'.

Code:
#!/usr/bin/env ksh
awk -v col=${1:-1} ' {print $(col)}'

This example accepts a column number from the command line and prints just that column from stdin. If no column number is given, it defaults to the first column.
Thanks for response

My Requirement is that AWK program should search "applyserver" string in the line's and return me the column number.so that i can use the column number to use and print that column number

I cannot pass the value from command line..
Last edited by Scott; 09-10-2010 at 01:55 PM.. Reason: Added code tags
# 5  
Old 09-05-2010
Sorry, misinterpreted your need. Maybe this sample will give you what you need:

Code:
awk '
        {
                if( match( $0, "apply_server=.*[ \t]" ) )    # search the input line for the pattern
                        print substr( $0, RSTART, RLENGTH );  
        }
'

If the match function finds apply_server= followed by any characters followed by a space or tab, it prints that part of the input line. On a successful match, RSTART is set to the index of the pattern matched and RLENGTH is set to the length of the string.

If you need to capture the string and use it, rather than printing it, you could assign the substring to a variable.

Hope this is more of what you needed.
This User Gave Thanks to agama For This Post:
mallak
# 6  
Old 09-05-2010
Thanks a lot

So i understood that using above code awk will scan each line and will return values 1 and 2

Code:
asnapply 1 2 3 apply_server=1 apply_schema=ASN
asnapply 1 2 3 apply_server=2 apply_schema=ASN

Thanks once again for the reply
Last edited by Scott; 09-10-2010 at 01:55 PM.. Reason: Added code tags
# 7  
Old 09-06-2010
Quote:
Originally Posted by mallak
Thanks a lot

So i understood that using above code awk will scan each line and will return values 1 and 2

asnapply 1 2 3 apply_schema=ASN
asnapply 1 2 3 apply_server=2 apply_schema=ASN

Thanks once again for the reply
No, it will find the whole string apply_server=1; If you need it to find just the value after the equal, use this:

Code:
split( substr( $0, RSTART, RLENGTH ), a, "=");   # split the token at the =
value = a[2];                           # everything after equal is in a[2]

This User Gave Thanks to agama For This Post:
mallak
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