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using sed in shell script

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# 1  
Old 09-01-2010
using sed in shell script
Hi all,

I have files with the following names;
Code:
afgcxa.pem4jan.rain.nc  
afgcxa.pem4feb.rain.nc    
afgcxa.pem4mar.rain.nc      
afgcxa.pem4apr.rain.nc

I want to rename them to
Code:
afgcxa.pem4-01.jan.rain.nc  
afgcxa.pem4-02.feb.rain.nc    
afgcxa.pem4-03.mar.rain.nc      
afgcxa.pem4-04.apr.rain.nc

I've been able to rename them as I require but only know how to do it "manually" i.e. one-by-one
Code:
mth="jan"
for file in $(ls *$mth.rain.nc); do
 mv $file $(echo $file | sed 's/'$mth'/-02.'$mth'/g')
done

The question is - how can i do this automatically so that sed reads jan, feb, mar etc? Also, how do i perform a counter i.e. 01, 02, 03?

Thanks, Muhammad.


Moderator's Comments:
Mod Comment Please use code tags, thank you
Last edited by Franklin52; 09-01-2010 at 08:33 AM..
# 2  
Old 09-01-2010
You can use the following script

Code:
 
#!/bin/ksh
integer j=1
for i in jan feb mar apr
do
infile=`ls afgcx*|grep $i`
mv $infile afgcxa.pem4-0$j.$i.rain.nc
j=j+1
done

This User Gave Thanks to malikshahid85 For This Post:
Muhammad Rahiz
# 3  
Old 09-02-2010
Thanks malikshahid85!

Is there a way to print the digits as 01, 02, 03 etc instead of 1, 2, 3? I know that independently I could use printf e.g.

Code:
printf "%02d" 4

but how do i incorporate this in the code?

Alternatively, how can I save results of echo or printf as variable?

Thanks.
# 4  
Old 09-02-2010
simple alternative to printf

Code:
typeset -Z2 j=1

This User Gave Thanks to frank_rizzo For This Post:
Muhammad Rahiz
# 5  
Old 09-02-2010
Code:
#!/bin/ksh
integer j=1
for i in jan feb mar apr may jun jul aug sep oct nov dec
do
  mon=$(printf "%02d" $j)
  infile=$(ls afgcx* |grep $i)
  mv $infile afgcxa.pem4-$mon.$i.rain.nc
  j=j+1
done

This User Gave Thanks to rdcwayx For This Post:
Muhammad Rahiz
# 6  
Old 09-02-2010
wonderful - thanks everyone!
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