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# 1  
Old 09-01-2010
awk problem
Find the number of files with sizes > 100KB in /, /bin, /usr, /usr/bin
and /usr/sbin directories and output them in a two column format with the
name of the directory and the number of files.

i tried with awk
Code:
$>ls -lh | awk '/^-/ && $5 >= 100k {print $8 $5}'

but it is not working pls tell me what to do
Last edited by Franklin52; 09-01-2010 at 06:49 AM.. Reason: Please use code tags!
# 2  
Old 09-01-2010
I think this command returns what you need:
Code:
find / /usr /usr/bin /usr/sbin -type f -mindepth 1 -maxdepth 2 -size +99k -printf '%h\n' | sort | uniq -c

I am in a RH linux box.

Also you can check the this link, if you want to change something in the command above: find(1) - Linux man page

Regards.
# 3  
Old 09-02-2010
/usr/bin is included in /usr and / will include all other folders.

---------- Post updated at 02:36 PM ---------- Previous update was at 02:30 PM ----------

Code:
for i in / /usr /bin /usr/bin
do
  n=$(find $i -type f -size +100k |wc -l)
  echo $i $n
done

# 4  
Old 09-02-2010
I think your problem is that AWK cannot understand that "100k" is a abbreviation for a number.

Find is an excellent tool for what you are trying to do.

Mikeb
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