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How to handle one value below the other

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# 1  
Old 08-27-2010
How to handle one value below the other
Hi,

I, have an output with 3 different values each below the other like:
[root]# echo $bla
123
345
234

Each value is in one line and for the further processing I need every single value.
For example is there a way to grep line 2, like:
[root]# echo $bla | grep --line 2
345

Smilie

Thank you in advance
2retti
Last edited by 2retti; 08-27-2010 at 04:55 AM..
# 2  
Old 08-27-2010
Code:
echo $bla | awk 'BEGIN {tot=0} "totalvcpu" {tot=tot+$1} END {print tot}'

Just a example but it shows how to handle individual value.

You need to learn little advance in awk.
# 3  
Old 08-27-2010
Quote:
Originally Posted by pinga123
Code:
echo $bla | awk 'BEGIN {tot=0} "totalvcpu" {tot=tot+$1} END {print tot}'

Just a example but it shows how to handle individual value.

You need to learn little advance in awk.
Thats not what I need. I want to work with each line within a for-loop. There must be a way to print out a specific line by the number of the line.
Last edited by 2retti; 08-27-2010 at 05:07 AM..
# 4  
Old 08-27-2010
Code:
awk 'NR==2{print $0}' filename

This will display 2nd line of file named filename
This User Gave Thanks to pinga123 For This Post:
2retti
# 5  
Old 08-27-2010
Quote:
Originally Posted by pinga123
Code:
awk 'NR==2{print $0}' filename

This will display 2nd line of file named filename
Thank you!!!! Thats exactly what need!!!
# 6  
Old 08-27-2010
Another way of doing the same thing (compact one)

Code:
awk 'NR==2' filename

Another way of doing the same thing (complex one)

Code:
head -2 filename | tail -1

Last edited by pinga123; 08-27-2010 at 05:24 AM..
# 7  
Old 08-27-2010
for loop i shell (bash)
Code:
for V in $bla
do
    ((i++))
    echo "$i - V='$V'"
done

in one line
Code:
for V in $bla; do ((i++)); echo "$i - V='$V'"; done

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