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shell script to call perl script problems

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# 1  
Old 08-24-2010
shell script to call perl script problems

Ok, don't ask me why, but all calls to perl must be called by a shell script. Its really not ideal, but its what I have to work with.

Calling it isnt the issue, its passing in the arguments.

I have about 1000 perl scripts to call by a shell script. Right now, I'm executing the shell script and bringing in the entire perl script and its arguments as one string to be executed.

The shell script is simply


However, when I call a perl script with its arguments, its fails many times because of the way the shell script is resolving the passed arguments. For example. Here's the shell script ( executing a perl script:

Code: "/tmp/last/done*.txt"

When it gets executed by the shell script, the parameter of "/tmp/last/done*.txt" gets resolved as all the files that matches the regex. This caused the perl script to failed because its exepecting the argument "tmp/last/done*.txt" and not a list of files. The

I've tried to encapsulate the arguments in various double quotes, tick marks, single quotes, etc. but cannot get the proper results.

Code: ""/tmp/last/done*.txt"" \"/tmp/last/done*.txt\" '"/tmp/last/done*.txt"' ` "/tmp/last/done*.txt"`

I'd like to have a single shell script that could call a perl scripts with any number of arguments, but have it resolve the arguments correctly because the number of arguments varies greatly. Not only that, but there are over 1000 perl scripts that need to be called this way. Is there a simple way to do this? What am I missing?
# 2  
Old 08-24-2010

#!/usr/bin/env ksh

This should preserve any quoting that was done on the original command line. Assuming Ksh; bash might but untried.

Last edited by agama; 08-24-2010 at 01:24 AM.. Reason: added hash bang
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# 3  
Old 08-24-2010
Thanks! So far so good! Smilie

Can you explain to me the difference between




The $* I assumed took the entire string after the shell script and executed it. I've never used @ before.
# 4  
Old 08-24-2010
quoting from the Advanced Bash-Scripting Guide
All of the positional parameters, seen as a single word

"$*" must be quoted.

Same as $*, but each parameter is a quoted string, that is, the parameters are passed on intact, without interpretation or expansion. This means, among other things, that each parameter in the argument list is seen as a separate word.

Of course, "$@" should be quoted.
refer to their example for more details
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