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AWK pattern matching

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# 1  
Old 08-13-2010
AWK pattern matching
Hi,

How can I tell awk to print all lines/columns if column number 5 contains the word Monday?

I have tried

Code:
nawk -F, '$5==Monday' OFS=, myfile > outputfile

but that doesn't work (I am a newb!!)

Thanks,
# 2  
Old 08-13-2010
use :
Code:
awk -F, '{$5==Monday}1' OFS=, file

# 3  
Old 08-13-2010
Code:
awk -F, '{$5==Monday}1' OFS=, file > newfile

Doesn't seem to work. newfile just contains the same contents as file

Thanks,
# 4  
Old 08-13-2010
Post ur source file please
# 5  
Old 08-13-2010
Source File:

Code:
mr,bob,bobson,Monday,20,france
mrs,caroline,godsom,Monday,30,Germany
mrs,sarah,bishop,Wednesday,10,UK
mr,karl,jacobs,Thursday,29,spain
mr,trevor,duell,Monday,34,belgium
miss,kate,dartsen,Wednesday,76,Austria

Thanks,
# 6  
Old 08-13-2010
Quote:
Originally Posted by keenboy100
Hi,

How can I tell awk to print all lines/columns if column number 5 contains the word Monday?

I have tried

Code:
nawk -F, '$5==Monday' OFS=, myfile > outputfile

but that doesn't work (I am a newb!!)

Thanks,


Wrong field and lack of double quotes:
Code:
nawk -F, '$4=="Monday"' OFS=, myfile > outputfile

Last edited by Franklin52; 08-13-2010 at 11:56 AM.. Reason: adding quote OP
# 7  
Old 08-13-2010
Code:
 grep -E "(.[^,]*),(.[^,]*),(.[^,]*),[ \t]*Monday[ \t]*" file
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