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Need some help with a regex if loop problem

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Top Forums Shell Programming and Scripting Need some help with a regex if loop problem
# 1  
Old 08-06-2010
Need some help with a regex if loop problem
Need some help with a regex if loop problem.
File1:
Code:
2323
3232
4230
3230
4340
4343
233
32320

I want to print "Zero" if the number ends with a zero, but print "number" if it does not!
Code:
#!/bin/bash
/usr/bin/nawk '{
if ($1 ==/[0-9]+0\b/){
 print "Zero"}
else{
 print "number"}
}' File1

this code just prints out "Number" for each line! Help!
# 2  
Old 08-06-2010
One way:
Code:
awk '{print $0%10?"Number":"Zero"}' file

# 3  
Old 08-06-2010
Code:
awk '{if($0 ~ "0$") {print "Zero"} else {print "number"}}' yourfile

edit: one more:
Code:
sed "s/.*[1-9]$/number/g;s/.*0$/zero/g" yourfile


Moderator's Comments:
Mod Comment Please use code tags, thank you!
Last edited by Franklin52; 08-06-2010 at 02:44 PM..
# 4  
Old 08-06-2010
Quote:
Originally Posted by linuxkid
...I want to print "Zero" if the number ends with a zero, but print "number" if it does not!
Code:
#!/bin/bash
/usr/bin/nawk '{
if ($1 ==/[0-9]+0\b/){
 print "Zero"}
else{
 print "number"}
}' File1

this code just prints out "Number" for each line!
The "~" operator is for matching regular expressions.

Code:
$
$ awk '{if ($0 ~ /0$/) {print $0,"Zero"} else {print $0,"number"}}' f1
2323 number
3232 number
4230 Zero
3230 Zero
4340 Zero
4343 number
233 number
32320 Zero
$
$ # or alternatively -
$ awk '/0$/ {print $0,"Zero"} !/0$/ {print $0,"number"}' f1
2323 number
3232 number
4230 Zero
3230 Zero
4340 Zero
4343 number
233 number
32320 Zero
$
$

tyler_durden
# 5  
Old 08-08-2010
Code:
while read -r LINE
do
  case "$LINE" in
    *0 ) echo "zero";;
    *[1-9]) echo "number";;
  esac
done <"file"

# 6  
Old 08-09-2010
Quote:
Originally Posted by linuxkid
Need some help with a regex if loop problem.
File1:
Code:
2323
3232
4230
3230
4340
4343
233
32320

I want to print "Zero" if the number ends with a zero, but print "number" if it does not!
Code:
#!/bin/bash
/usr/bin/nawk '{
if ($1 ==/[0-9]+0\b/){
 print "Zero"}
else{
 print "number"}
}' File1

this code just prints out "Number" for each line! Help!
In addition to the operator error pointed out by durden_tyler, \b in an awk regular expression is an escape sequence which matches the backspace character (unlike in perl where it refers to a word boundary).
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