Find files of particular day


 
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# 1  
Old 08-03-2010
Find files of particular day

Hi,

I need to find all files of particular day lets say for 2nd august in below.

Code:
-rw-r--r--   1 skl  eusdc       8168 Aug  5 19:31    aabc123.txt
-rw-r--r--   1 skl  eusdc       4251 Aug  5 19:31    aabc124.txt
-rw-r--r--   1 skl  eusdc       4252 Aug  6 19:31    aabc125.txt
-rw-r--r--   1 skl  eusdc       3895 Aug  6 19:31    aabc213.txt
-rw-r--r--   1 skl  eusdc       3896 Aug  2 19:31    aabc456.txt
-rw-r--r--   1 skl  eusdc       3183 Aug  2 19:31    aabc63453.txt
-rw-r--r--   1 skl  eusdc       3184 Aug  2 19:31    aabcqwe.txt
-rw-r--r--   1 skl  eusdc       1047 Aug  3 07:30    mnbvcc.txt
-rw-r--r--   1 skl  eusdc       1048 Aug  3 07:30    as54633.txt
-rw-r--r--   1 skl  eusdc       1047 Aug  3 07:30    poiuy78.txt
-rw-r--r--   1 skl  eusdc       1048 Aug  3 07:30    sdfsd.doc
-rw-r--r--   1 skl  eusdc      10596 Aug  3 07:30   dfgd.txt
-rw-r--r--   1 skl  eusdc      10600 Aug  3 07:30   qweqw.doc


Last edited by pludi; 08-03-2010 at 09:55 AM.. Reason: code tags, please...
# 2  
Old 08-03-2010
Code:
grep " Aug 2 " inputfile

# 3  
Old 08-03-2010
i need to find all files of lets say Aug 2 and the counts for a particular string lets say "abc" is present in the files received for Aug 2
# 4  
Old 08-03-2010
How about:
Code:
ls -ld *abc* | grep "Aug  2"

# 5  
Old 08-04-2010
It just give me files of Aug 3. How about finding the total count of a string lets say "sachin" in all the files of Aug 3
# 6  
Old 08-04-2010
Try

Code:
$ ls -l | awk '/Aug  2/ { print $NF }' | grep -c 'sachin'

# 7  
Old 08-04-2010
It still does not answer my question. It looks for string 'sachin' in the filenames which is i dont want. I need to find total count of string 'sachin' in the text present inside the files not in the filenames.
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