Shell Programming and Scripting

 
company_ed_20100719.txt
company_ea_20100719.txt
company_bi_20100719.txt

 
ed with EmployeeDetails
ea with EmployeeAddress
bi with BankInfomration

 
company_ EmployeeDetails _20100719.txt
company_ EmployeeAddress _20100719.txt
company_ BankInfomration _20100719.txt

 
if [ file name contains ‘ed' ] then
 Replace ed with EmplaoyeeDetails
else if [file name contains ‘ea' ] then
Replace ea with EmplaoyeeAddress
else if  [file name contains ‘bi' ] then
Replace bi with BankInformation
fi

for f in *_*_*.txt; do
  fp=${f%%_*} rst=${f##*_} 
  case $f in
    *_ed_* ) mv -- "$f" "$fp"_EmployeeDetails_"$rst";;
    *_ea_* ) mv -- "$f" "$fp"_EmployeeAddress_"$rst";;
    *_bi_* ) mv -- "$f" "$fp"_BankInfomration_"$rst";;
  esac
done

for filename in `ls *`
do
if [`grep ea "filename"`]
echo filename |sed 's/ea/EmployeeAddress/'
elif [`grep ed "filename"`]
echo filename | sed 's/ed/EmployeeDetails/'
elif [`grep bi "filename"`]
echo filename | sed 's/bi/BankingInformation/'
fi
done

#!/bin/bash
my=("ed" "ea" "bi")
newmy=("EmployeeDetails" "EmployeeAddress" "BankInfomration")
ix=0
for i in ${my[@]}
  do
   myfile=$(ls -1 company* | grep $i)
   newfile=$(echo $myfile | sed "s/^\(.*_\).*\(_.*\)/\1 ${newmy[ix]} \2/")
   mv -v "$myfile" "$newfile"
   ((ix++))
  done