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# 1  
Old 07-08-2010
Print the previous line
My requirement is that when ever search criteria matchs in log file, the previous line just above the search word as well as search word should be print.

sample log file

Code:
--03-19T11:26  xxx    create version "a.sh@@/main/6"
  "104157 "
--03-18T16:01  xxx    create version "a.sh@@/main/5"
  "104157 "
--03-16T12:51  xxx    create version "a.sh@@/main/4"
  "874569"
--03-09T17:49  xxx    create version "a.sh@@/main/3"
  "874569"
--02-23T07:21  xxx  create version b.sh@@/main/14
  "94145"
--02-22T07:12  xxx  create version "b.sh@@/main/13"
  "94145"
--02-21T00:10  xxx    create version "b.sh@@/main/12"
  "2010"



No if i search for 94145, then output shoul be -

Code:
--02-23T07:21  xxx  create version b.sh@@/main/14    <-- previous line   
  "94145"                                                              <-- search critria
--02-22T07:12  xxx  create version b.sh@@/main/13   <-- previous line   
  "94145"                                                  <-- search critria


another example, if user search for 2010, then output should be -

Code:
--02-21T00:10  xxx    create version "b.sh@@/main/12"
  "2010"

Any kind of help will be appriciated.

Thanks in advance.
Last edited by jadoo_c2; 07-08-2010 at 09:44 AM..
# 2  
Old 07-08-2010
Code:
awk '$0 ~ v { print p RS $0 }
{ p = $0 }' v=94145 infile

And of course, you may need to make the search more specific.
# 3  
Old 07-08-2010
Thanks!!

Can you please tell me should i use your suggestion as a awk script or as a command ??

---------- Post updated at 06:20 PM ---------- Previous update was at 06:19 PM ----------

Can yopu please ellobrate it more??
# 4  
Old 07-08-2010
Hi, Try this
Code:
grep -B1 "94145" testfile

# 5  
Old 07-08-2010
Quote:
Originally Posted by pravin27
Hi, Try this
Code:
grep -B1 "94145" testfile


Consider that -A/B are supported only by GNU grep.

---------- Post updated at 02:57 PM ---------- Previous update was at 02:56 PM ----------
Quote:
Originally Posted by jadoo_c2
Thanks!!

Can you please tell me should i use your suggestion as a awk script or as a command ??

---------- Post updated at 06:20 PM ---------- Previous update was at 06:19 PM ----------

Can yopu please ellobrate it more??
Just run the script on the command line:

Code:
awk '$0 ~ v { print p RS $0 } { p = $0 }' v=94145 <your_log_file_name>

# 6  
Old 07-08-2010
I tried what you said and got following error message

Code:
 
$ awk '$0 ~ v { print p RS $0 } { p = $0 }' v=94145 log
awk: syntax error near line 1
awk: bailing out near line 1
$

Please remember that i am using K shell and Sun Solaries as OS
# 7  
Old 07-08-2010
OK, just use nawk instead of awk.
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