Shell Programming and Scripting

Hello UNIX experts,

I have 124 text files in a directory. I want to extract the 45678th line of all the files sequentialy by file names. The extracted lines should be printed in the output file on seperate lines.

e.g. The input Files are one.txt, two.txt, three.txt, four.txt
The cat of four files are

Code:

one.txt  
AAAA
BBBB
CCCC
DDDD

two.txt
1111
2222
3333
4444

three.txt
aaaa
bbbb
cccc
dddd

four.txt
bcde
cdef
defg
efgh

The desired output in output.txt is (3rd line of all files one by one on seperate lines. Keep 6 spaces and print the filename at the end)

Code:

CCCC      one.txt       
3333      two.txt 
cccc      three.txt  
defg      four.txt

Thanks in advance.

It seems like homework... but anyway:

Code:

awk 'FNR==45678{print $0,FILENAME}' *.txt > output.txt