Shell Programming and Scripting

echo "                                                                                                   MENU
                                                                                                            1) no. 1"

#!/usr/local/bin/ksh93

# option 1: ls
# option 2: ls -l
# option 10: exit
# options 3-10: undefined

function menu {

  for ((i=1;i<=10;i++)); do printf "%80s\n" "$i. option $i "; done

  printf "%77s" " ->  "

  read opt

   case $opt in
	"1") ls; menu;;
	"2") ls -l; menu;;
	"10") exit;;
	*) echo "Invalid or undefined option!"; menu;;
   esac

}


#printf "\n\n\n\n\n\n\n\n\n\n\n\n\n"
menu