I'm writing unix script, it should find exact matching in search string. Looks simple but when i started i'm stuck to find the exact match character string.
The unix script reads the records from DB Table. The table will have values something likes these
For the Feed A, I have to look feed file name in "feed_file_20100630.txt", for B "feed_file1_100630.txt", for C "feed_file2_2010Jun30.txt". For the tomorrow month and Data gets changed (tomorrow is 1 Jul 2010).
After reading these values from DB, i have to find what format it has and replace with as of today's date format, look the file is exist in share folder.
I try to implement this with awk
for the Feed B it goes to Case 1, but it suppose to go to Case 2.
If i reverse the order for the Feed A, it suppose to go to case 1, but goes to case 2.
I'm unable to achieve this using "-w" option in "grep" command.
I hope i have explained clearly.
Let me know how to resolve my problem
Last edited by radoulov; 06-30-2010 at 06:38 AM..
Reason: Please use code tags!
Actually in my example i have used "_" before for all date format. But actually some cases it is like (yyyymmdd_fee_file2.dat). In some cases it is like hh_mm_ss:yyyymmmdd also. So this wouldnt work out for my problem.
I have somehow close to my solution using the re interval option to awk. If some1 has better solution. Warm welcome for it.
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