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Shell Programming and Scripting

Moving first position in a file to the last position

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# 8  
Old 06-28-2010
yes, awk is probably faster (even in this simple case? i'm not sure),
but your awk script/line misses to give the ending needed | on each line.
# 9  
Old 06-28-2010
Quote:
Originally Posted by daPeach
yes, awk is probably faster (even in this simple case? i'm not sure),
but your awk script/line misses to give the ending needed | on each line.
That's fine, it's not so difficult to update it, if the requester understands the code.

I have corrected it in previous post. .Smilie
# 10  
Old 06-28-2010
err Smilie
now it adds an extra | between previously last field and kind_of_a_time stamp
# 11  
Old 06-28-2010
Java
Quote:
Originally Posted by daPeach
using bash:
Code:
cat pparthiv_file
2010_06_4010093_001_001|10|ABCDEFGH|9|4010093||0040400||31.12.2009|S|O|X||||20100602093851-31.12.2009|XXBBFC|EFG||||00001|
2010_06_4010162_001_001|11|ABCDEFGH|9|4010162||0040400||31.12.2009|S|O|X||||20100602093851-31.12.2009|XXBBFC|EFG||||00002|
2010_06_4010163_001_001|17|ABCDEFGH|9|4010163||0040400||31.12.2009|S|O|X||||20100602093851-31.12.2009|XXBBFC|EFG||||00003|

while IFS='|' read -a line; do
   printf '%s|' "${line[@]:1}"
   printf '%s|\n' "${line[@]::1}"
done < pparthiv_file

How would i print the output to a file?Smilie
# 12  
Old 06-29-2010
Code:
while IFS='|' read -a line; do
   printf '%s|' "${line[@]:1}"
   printf '%s|\n' "${line[@]::1}"
done < pparthiv_file > anyother_file
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