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Problem with Ksh scripting

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# 1  
Old 06-07-2010
Question [Solved] Problem with Ksh scripting


Below is the code for my script

for file in "file1.txt" "file2.txt" "file3.txt" "file4.txt"
 L="$(tail -1 $file)"
 echo $NUM
 echo $DAT

Now here,suppose for file1.txt
L will have data like 56|06-07-2010
So, it should be
NUM as 56 & DAT as 06-07-2010

but through the script NUM is getting NULL value and DAT is having 56|06-07-2010 although when am running it without script all works fine...Please tel wher am i wrong..... Smilie
# 2  
Old 06-07-2010
What is your login shell? Post output of ps command.
# 3  
Old 06-07-2010
What happens if you escape the | like so:

This User Gave Thanks to Scrutinizer For This Post:
# 4  
Old 06-07-2010
 ls file[1-4].txt |xargs -i awk -F \| '{a=$1;b=$2} END {print a,b}' {}

# 5  
Old 06-07-2010
Thanks all.....!!!Smilie

My login shell is ksh.....!!!
scrutinizer's "\" is working fine for me......but why is it required in scripting but not in normal input???

C u all...!
# 6  
Old 06-07-2010
I don't know, perhaps you are not using the exact same ksh as you are using in your script?

In this case whether | should be escaped in variable expansion is at least a grey area and probably is open to interpretation. In this case I would just escape it - even if it is not required - just to avoid problems. This should work in any Posix shell.
# 7  
Old 06-07-2010

Thanks Smilie

i jus give ksh to change my shell.....anyways now its working fine...may be that escape thing was the problem.

NB: Please if can any one let me know how to close threads so that this will signify that my problem is solved..!

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