Shell Programming and Scripting

java <my_java_class_file_without_extension> <arg1> <arg2> ... ...

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$ # display the content of the Java source file
$ cat -n ShowArgs.java
     1  /*
     2  A java program that displays the input parameters passed to it.
     3  */
     4  public class ShowArgs {
     5    public static void main (String[] args) {
     6      System.out.println("No. of input parameters = "+args.length);
     7      if (args.length > 0) {
     8        System.out.println("The input parameters are listed below:");
     9        for (int i=0; i<=args.length-1; i++) {
    10          System.out.println("Parameter # "+i+" => "+args[i]);
    11        }
    12      }
    13    }
    14  }
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$ # see if I have the corresponding class file
$ ls -1 ShowArgs*
ShowArgs.class
ShowArgs.java
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$ # Yes, I do. So just launch it now by feeding the *class* file to "java"
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$ java ShowArgs
No. of input parameters = 0
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$ # once more
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$ java ShowArgs the quick 123.45 brown fox -9e10 jumps "over the lazy" dog
No. of input parameters = 9
The input parameters are listed below:
Parameter # 0 => the
Parameter # 1 => quick
Parameter # 2 => 123.45
Parameter # 3 => brown
Parameter # 4 => fox
Parameter # 5 => -9e10
Parameter # 6 => jumps
Parameter # 7 => over the lazy
Parameter # 8 => dog
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