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Cutting out text from specific portion on filename

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# 1  
Old 05-12-2010
Cutting out text from specific portion on filename
Hi,

how do I go about cutting out the first numeric characters after the word "access"?

access1005101228.merged-00.15.17.86.d8.b8.log.gz
# 2  
Old 05-12-2010
Code:
$ echo access1005101228.merged-00.15.17.86.d8.b8.log.gz | cut -c7-12
100510

# 3  
Old 05-12-2010
oh sorry

did not make it clear that I am running a find command and there might be different directories before the actual filename so a cut will not work
# 4  
Old 05-12-2010
This command gives the 6 characters after the word access:
Code:
sed -e 's/.*access\(......\).*/\1/'

This User Gave Thanks to Franklin52 For This Post:
GermanJulian
# 5  
Old 05-12-2010
Code:
echo 'access1005101228.merged-00.15.17.86.d8.b8.log.gz' | sed 's/.*access\([^.][^.]*\).*/\1/'

# 6  
Old 05-12-2010
MySQL
Bash solution is more simple Smilie

Code:
a="access1005101228.merged-00.15.17.86.d8.b8.log.gz"

Code:
echo ${a:6:6}
100510

# 7  
Old 05-12-2010
Quote:
Originally Posted by ygemici
Bash solution is more simple Smilie

Code:
a="access1005101228.merged-00.15.17.86.d8.b8.log.gz"

Code:
echo ${a:6:6}
100510

As mentioned by the OP:

there might be different directories before the actual filename
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