I usually just browse the forum/google for answers, however I've been stuck on a problem for a number of hours now and I've decided to join up and actually ask I've searched the forum ad naseum in an attempt to find answer to my query, however so far I have been unsuccessful.
I'm no expert infact I've been writing shell scripts for all of 2 days.
Basically I want to read in 3 values, set that to a sequence, output to a file then read the values of various lines in as I want to later on.
However, my problem is as such.
When I read in a value of -20.0 it gets set to -20 This is not acceptable for me.
How can I get the format of x.0 bearing in mind sometimes the first value will be x.y
Thanks.
Last edited by Scott; 04-28-2010 at 07:24 PM..
Reason: Added code tags
You can use printf to ensure that numbers have a specified precision:
For your situation, if you require all numbers to be similarly formated, perhaps:
Regards,
Alister
It would have made more sense to just join up a few hours ago and ask rather than assure myself I could figure it out. Oh well, what doesn't kill us...
Hi! I'm trying to do this:
1 -
2 -
3 -
4 -
5 -
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seq 1 20 > filename.txt
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Hi.
I'm receive thats error on my PC.
lp: cannot lock /usr/spool/lpd/printer1/.seq
This PC is a Windows pc running lpd on port 515.
That its means?
Thanks.
PD. Sorry for my english! (0 Replies)
Hi,
Normally, I will manually to use "ll" command to list the following file from \FILE\CACHE\ directory and check the jump seq. Can I write a script to loop or/and check jump seq file (if jumped seq and show "missing seq no" message for me)
-rw-rw----+ 1 user develop 14012 Sep 4... (1 Reply)