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How to remove all words starting from a matching word in a line

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# 1  
Old 04-23-2010
How to remove all words starting from a matching word in a line
Hi Guys,

I have a file like this:

Code:
 
wwwe 1 ioie ewew yyy uuu 88
erehrlk 4 ihoiwhe lkjhassad lkhsad yyy mmm 45
jhash lhasdhs lkhsdkjsn ouiyrshroi oihoihswodnw oiyhewe yyy ggg 77

I want to remove everything after "yyy" and including "yyy" from each line in the file.
So I want:

Code:
wwwe 1 ioie ewew 
erehrlk 4 ihoiwhe lkjhassad lkhsad 
jhash lhasdhs lkhsdkjsn ouiyrshroi oihoihswodnw oiyhewe


How do I do this?

Thanks.
# 2  
Old 04-23-2010
Hi.

You can do it with sed:
Code:
$ cat file1
wwwe 1 ioie ewew yyy uuu 88
erehrlk 4 ihoiwhe lkjhassad lkhsad yyy mmm 45
jhash lhasdhs lkhsdkjsn ouiyrshroi oihoihswodnw oiyhewe yyy ggg 77

$ sed "s/yyy.*//" file1
wwwe 1 ioie ewew 
erehrlk 4 ihoiwhe lkjhassad lkhsad 
jhash lhasdhs lkhsdkjsn ouiyrshroi oihoihswodnw oiyhewe 

# I suppose more accurate would be
sed "s/\wyyy.*//" file1
# or
sed "s/  *yyy.*//" file1

Last edited by Scott; 04-23-2010 at 08:07 PM..
# 3  
Old 04-24-2010
You can use this to get everything before the pattern yyy.
Here I used yyy pattern as field seperator.

Code:
 
cat file|awk -F 'yyy' '{print $1}'

Thanks
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