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Regex for for integer from 0-7 except 2

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# 1  
Old 04-16-2010
Regex for for integer from 0-7 except 2
Hi,

I am trying to use a regular exp to match any number between 0 and 7 except 2......
I am using:

echo $myvar | egrep "{1}[0-1]{1}[3-7]"Which isnt working....

Please can someone help?
Thanks

yonderboy
# 2  
Old 04-16-2010
MySQL
This is the answer you are seeking

Code:
egrep -v "[289]"

# 3  
Old 04-16-2010
You can try in Sed
Code:
$cat file_name
0
1
2
3
4
5
6
7
sed -n '/2/n; /[0-7]/p' file_name
0
1
3
4
5
6
7

Last edited by posix; 04-16-2010 at 02:10 AM.. Reason: misprint 9 in place of 7
# 4  
Old 04-16-2010
Fantastic, thank you. My code is working.

---------- Post updated at 03:20 PM ---------- Previous update was at 03:08 PM ----------

Just out of interest, can you explain how the first solution works?
# 5  
Old 04-16-2010
The option -v make grep to search for everything that don't match the regexp, in this case, it prints every line that not contains chars 2, 8 or 9
# 6  
Old 04-16-2010
grep '[013-7]'

js.
# 7  
Old 04-16-2010
Quote:
Originally Posted by ungalnanban
This is the answer you are seeking

Code:
egrep -v "[289]"

Hahaha. this also matches everything else under the sun, including:

jdlkflkflkdl320kkjkjlk&%#jkvjkjfdfdfd

Smilie

.... which is not what the original poster asked for Smilie

---------- Post updated at 15:59 ---------- Previous update was at 15:53 ----------

The regex to match 0-7 but not any 2 is:
Code:
[013-7]

to match one or more of the above, use:
Code:
[013-7]+



Quote:
[013-7]+

Options: case insensitive; free-spacing

Match a single character present in the list below «[013-7]+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
One of the characters “01” «01»
A character in the range between “3” and “7” «3-7»
Last edited by Neo; 04-16-2010 at 01:01 PM.. Reason: fixed typo (7 not 9)
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