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Formatting a date

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# 1  
Old 04-12-2010
Formatting a date
Hi,

the date value retrieved by a parameter from the table is of the format dd/mm/yyyy. please let me know how to convert this to YYYYMMDD using sed

thanks
# 2  
Old 04-12-2010
Code:
$ echo 31/01/2010 | sed "s;\([0-9]\{2\}\)/\([0-9]\{2\}\)/\([0-9]\{4\}\);\3\2\1;"
20100131
$ echo 31/01/2010 | awk -F"/" ' { print $3$2$1 } '
20100131

# 3  
Old 04-12-2010
you may try something like this :

sed -e 's/(\d+)\/(\d+)\/(\d+)/$3$2$1/g' | echo $PARAM

It has been assumed here that the date value is retrieved in the parameter PARAM
# 4  
Old 04-12-2010
Quote:
Originally Posted by m_kapur83
you may try something like this :

sed -e 's/(\d+)\/(\d+)\/(\d+)/$3$2$1/g' | echo $PARAM

It has been assumed here that the date value is retrieved in the parameter PARAM
A pipeline that flows upstream? Smilie
# 5  
Old 04-12-2010
oops...plzz chng it to

echo $PARAM|sed -e 's/(\d+)\/(\d+)\/(\d+)/$3$2$1/g'
Smilie
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