How to check that passed parameters all have the same extension?
My brain has given up; what's the simplest shell script needed to produce the above output, i.e. iterate through positional parameters, comparing their file extensions for similarity?
I know it's wrong, but here's my thought process:
Thanks in advance...
---------- Post updated at 01:21 PM ---------- Previous update was at 12:00 PM ----------
Nearly there! Now I just need it to work when files are without an extension, too (currently this would say they are NOT alike):
---------- Post updated at 01:50 PM ---------- Previous update was at 01:21 PM ----------
you can try for extension check
if u want to check for the file name replace $2 with $1.
This script can me made shorter if we use array and count the var also.. .. for better result.
The following is a sh solution that should be portable to most reasonably posix-compliant shells, and which should use nothing but sh built-ins to do its job.
With 0 or 1 argument, the result is always a match. With two or more, all extensions must match. The extension for "file.1.2" is ".1.2" and not ".2". All filenames with absent extensions match each other (which is the same semantic as that used by the echo|sed|uniq|wc pipeline in your earlier solution).
e=extension of current filename
set_e=function to set e
ext=extension which all filenames must match
f=current filename
You can then use the exit status to echo or proceed accordingly (or you can just insert the echo statements into the code, if you like).
Regards,
Alister
Last edited by alister; 04-07-2010 at 03:36 PM..
Reason: removed shift
#!/bin/bash
function check_num_args()
{
if ; then
echo "Please provide a file name"
else
treat_as_file $*
fi
}
function treat_as_file()
{
numFiles=$#
for((i=1;i<=$numFiles;i++));do
echo $i
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