file naming question


 
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# 1  
Old 03-31-2010
file naming question

Hi,
I need some help!

I have a file in which i im splitting into 20 different files each called

model_001.in
model_002.in
etc...

i would like to make directory for each file using only the name and not the extension so that the directory names are

model_001
model_002
etc.

then put the *.in files inside of the corresponding directories. Sorry if this is a naive question but it will really help alot. Thanks
# 2  
Old 03-31-2010
Code:
file=model_001.in
file_without_extn=${file%.*}

you can mkdir it and process accordingly.
# 3  
Old 03-31-2010
Code:
#!/bin/ksh or bash or ...
for f in *.in
do
     d=${f%.*}
     [ ! -d "$d" ] && mkdir "$d" 2>/dev/null
     [ ! -d "$d" ] && echo error $d && continue
     mv -f "$f" "$d" 2>/dev/null
done

# 4  
Old 03-31-2010
Quote:
Originally Posted by kshji
Code:
#!/bin/ksh or bash or ...
for f in *.in
do
     d=${f%.*}
     [ ! -d "$d" ] && mkdir "$d" 2>/dev/null
     [ ! -d "$d" ] && echo error $d && continue
     mv -f "$f" "$d" 2>/dev/null
done

If you are going to echo "error", it would be better to simply not redirect mkdir or mv standard error , so that a meaningful error message is returned. Also, it's probably not a bad idea to abort if any mkdir or mv command fails.

I suggest:
Code:
#!/bin/sh

set -e
for f in *.in
do
     d=${f%.*}
     if [ ! -d "$d" ]; then
        mkdir "$d" 
     fi
     mv -f "$f" "$d"
done

Regards,
Alister
# 5  
Old 04-01-2010
So im trying to understand the script....
so in the line:

d=${f%.*}


the "f%.*" part of it represents the name and not the extension part of it?

Thanks
# 6  
Old 04-01-2010
MySQL

Quote:
Originally Posted by olifu02
So im trying to understand the script....
so in the line:

d=${f%.*}


the "f%.*" part of it represents the name and not the extension part of it?

Thanks
Yes you understand correctly
For example

Code:
f=model_001.in

Code:
d=${f%_*.*}

Code:
echo $d
model


So we divided that

f%
means --> all characters before _ and this is we want to part (for use it % character)
* --> other all characters from . (point)
* --> other all characters after . (point)
# 7  
Old 04-01-2010
Thanks one more thing.

What do the ! and -d mean in the line

Code:
if [ ! -d "$d" ]; then

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