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Tracing a function call

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# 1  
Old 03-19-2010
Tracing a function call


I am hoping someone can explain this to me as I am struggling to understand it.

I had a problem today with needing to trace a ksh script that was dotting in a function that was writing to stdout. The problem was it was being run in a sub shell and the output was being parsed by the calling script so I could not have any trace output on stdout.

On a hunch I tried this solution to log the function's trace to file and it worked but I don't know why, can anyone enlighten me?

The code: -

TX5XN:/home/brad/ksh_stuff>cat trace_2

    set -x
    echo "This goes to stdout from func"
    set +x
    echo "=============================" >&2
} 2>> set.log2

echo "This goes to stdout from main body"

for x in 1 2 3 4 5

The output to stdout: -

TX5XN:/home/brad/ksh_stuff> trace_2  
This goes to stdout from main body
This goes to stdout from func
This goes to stdout from func
This goes to stdout from func
This goes to stdout from func
This goes to stdout from func

The trace log: -

TX5XN:/home/brad/ksh_stuff>cat set.log2
trace_2:5-echo 'This goes to stdout from func'
trace_2:5-echo 'This goes to stdout from func'
trace_2:5-echo 'This goes to stdout from func'
trace_2:5-echo 'This goes to stdout from func'
trace_2:5-echo 'This goes to stdout from func'

# 2  
Old 03-19-2010

Your code redirects stderr for the function to set.log2, so that's where all the trace output will be found. If the calling script is only reading stdout (from a pipe or coprocesses or fifo), you don't need that redirection.

The shell shall write to standard error a trace for each command after it expands the command and before it executes it. It is unspecified whether the command that turns tracing off is traced.
-- Shell Command Language


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