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how to get what date was 28 days ago of the current system date IN UNIX

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Top Forums Shell Programming and Scripting how to get what date was 28 days ago of the current system date IN UNIX
# 8  
Old 03-18-2010
Quote:
Originally Posted by murugaperumal
Code:
find -mtime +28 -exec rm {} \;

rm ??? Smilie SmilieSmilieSmilieSmilie
# 9  
Old 03-18-2010
Quote:
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010,
Quote:
find -mtime +28 -exec rm {} \;
This will just delete all files before 28 days..ie, it will delete all files before 1st of March...not jsut the files of March1st, as per the example mentioned.

Hope its clear for you.

The correct one should be

Code:
find . -mtime 28 -exec rm {} \;


Also, just go with
Code:
find . -mtime 28 -exec ls -l \;

before executing rm , just to make sure that the files listed are what you need to delete.
# 10  
Old 03-18-2010
Thank you Dennis, When I execute the perl code it is giving the correct date stamp.

Code:
$
$ uname -a
SunOS ccluatdwunix2 5.10 Generic_141414-08 sun4v sparc SUNW,T5240
$
$ var=`perl -w -e '$d=28*86400;@t=localtime (time -$d); printf "%d%.2d%.2d", $t[5]+1900,$t[4]+1,$t[3];'`
$
$ echo $var
20100218
$

Could you please help me how can I get the date stamp like 18-Feb-2010.
Last edited by pludi; 03-18-2010 at 09:48 AM.. Reason: code tags, please...
kandi.reddy
# 11  
Old 03-18-2010
Quote:
Originally Posted by dennis.jacob
This will just delete all files before 28 days..ie, it will delete all files before 1st of March...not jsut the files of March1st, as per the example mentioned.

Hope its clear for you.

The correct one should be

Code:
find . -mtime 28 -exec rm {} \;

Also, just go with
Code:
find . -mtime 28 -exec ls -l \;

before executing rm , just to make sure that the files listed are what you need to delete.
DON'T YOU KNOW THAT IS THE ACTUAL REQUIREMENT.
READ THE FOLLOWING LINE OF THE POSTER's POST.
 Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010,

FOR THE ABOVE QUESTION ONLY I REPLIED.

I KNOW HOW TO GET THE PREVIOUS 28TH DAY.
DONT YOU KNOW THAT THE COMMAND WHICH I GAVE WILL GIVE THE 28TH DAY AGO? SmilieSmilie
# 12  
Old 03-18-2010
Try:

Code:
perl -w  -e '@m = qw(Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec); $d=28*86400;@t=localtime (time -$d); printf "%2d-%s-%d", $t[3],$m[$t[4]],$t[5]+1900;'



---------- Post updated at 17:43 ---------- Previous update was at 17:32 ----------
Quote:
Originally Posted by murugaperumal
DON'T YOU KNOW THAT IS THE ACTUAL REQUIREMENT.
READ THE FOLLOWING LINE OF THE POSTER's POST.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010,

FOR THE ABOVE QUESTION ONLY I REPLIED.

I KNOW HOW TO GET THE PREVIOUS 28TH DAY.
DONT YOU KNOW THAT THE COMMAND WHICH I GAVE WILL GIVE THE 28TH DAY AGO? SmilieSmilie
Hello,


Code:
If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010,

I just said your command below will delete all files with mtime not just the exact 28th day before current date but also the files before that.ie, say all files on Jan, Feb of 2010, 2009 , 2008 etc...

Code:
find -mtime +28 -exec rm {} \;


If the files has to be deleted which has got mtime eaxctly 28 days, you have to use

Code:
find . -name "*" -mtime 28

# 13  
Old 03-18-2010
Quote:
If the files has to be deleted which has got mtime eaxctly 28 days, you have to use

Code:
find . -name "*" -mtime 28
This does NOT match the requirement. You will get different results according to what time of day you run the command because the 28 days is measured from the current system time.
Also the command needs "-type f" and an understanding of the directory structure.


We need to know what the O/P is going to do with the date. Is it part of a filename or the actual directory timestamp of the file???

Btw: The perl solution at the top of post #12 appears to work to the latest version of the requirement.
Last edited by methyl; 03-18-2010 at 11:13 AM..
# 14  
Old 03-18-2010
once you got the date i hope you can do something like this, but surely there will be an easy approach.

Code:
da="20100218"
day=`echo $da |cut -c 7,8`
mon=`echo $da |cut -c 5,6`
yea=`echo $da |cut -c 1-4`

Mon=`cal $mon $yea | head -1 | awk '{ print substr($1,1,3) }'`

ddmonyyyy=$day"-"$Mon"-"$yea

echo $ddmonyyyy
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