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# 1  
Old 03-12-2010
Find a special string in a text document
Hi,

i got stuck in creating a search job.

I have a text file which looks like this:
Code:
======================
Backup - OK -
Backup - OK -
Backup - ERROR -
Backup - WARNING -
======================

I want to search the text file for the string ERROR.
If this string is present in the text file, there should be an output.

I tried following in the bash, but it won't work. Maybe you have an idea?

Code:
if [ "$(cat database.txt)" = "ERROR" ];
then    
 echo "Found an ERROR."
elif [ "$(cat database.txt)" = "WARNING" ];
then
 echo "Found a WARNING".
else
 echo "Backup sucessful."
fi

I get always the output: Backup sucessful, but in the text file the string ERROR is present.

Thanks for your help.

greetz
lino

edit by bakunin: please use code-tags for code-parts or output. Thank you.
# 2  
Old 03-12-2010
You can use the following way.
consider that the file is having the content as follows

Code:
cat file
ERROR
hai
this is test
WARNING

Code:
while read line
do
if [ "$line" == "ERROR" -o "$line" == "WARNING" ]
then
        echo "Matched line is $line"
fi
done < file

Here I put a sample code for matching a particular word only.
So you need to do some work around.
Instead of using = you have to use ==
Last edited by thillai_selvan; 03-12-2010 at 08:16 AM..
# 3  
Old 03-12-2010
Code:
grep 'ERROR' file

# 4  
Old 03-12-2010
Quote:
Originally Posted by lnino
Code:
if [ "$(cat database.txt)" = "ERROR" ];

The problem with this is that you are asking if "cat database.txt" is exactly "ERROR", which of course it isn't. For tasks like yours, where you want to know if a text contains a certain string there is a Unix command named "grep". Have a look at the man page for grep to find out what you could do with it (which is quite a lot, i can assure you).

Your code should look like:

Code:
if [ $(grep -c "ERROR" database.txt) = 0 ]; then
     print - "no error found"
else
     print - "error found"
fi

Similar for "WARNING", etc..

I hope this helps (and you don't forget your code-tags from now on ;-) ).

bakunin
# 5  
Old 03-12-2010
MySQL
Try this,

Code:
result=`grep -w "ERROR" database.txt`
err=$?
result=`grep -w "WARNING" database.txt`
war=$?
if [ $err -eq 0 ]
then
 echo "Found an ERROR."
elif [ $war -eq 0 ]
then
 echo "Found a WARNING".
else
 echo "Backup sucessful."
fi

# 6  
Old 03-12-2010
You can use the following code

Code:
while read line
do

`echo $line | grep "ERROR" >/dev/null`
if [  $? -eq  0 ];
then
        echo "Matched ERROR the line is $line"
fi
done < file

# 7  
Old 03-12-2010
Hey guys,

thanks a lot for the help.

I will try with method works best in my situation.

From now, I will use code boxes for my code. :-)

greetz
lnino

---------- Post updated at 10:19 AM ---------- Previous update was at 08:20 AM ----------

Hi.

I have now implemented the code.
I used the code of bakunin.

I am interested in another feature.

Is it possible to count how often the word ERROR has been found in the text file?

Thanks a lot

greetz
lnino
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