10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
If I am running a bash command, and some awk getting the ethernet adapter on the local machine. It works fine. But if I will run it from the remote, it is EMPTY on echo and throwing error in grep.
Thank you
This work perfectly fine
$ f=`/sbin/ip a|grep 127.127 | awk '{print $NF }' ` ; ip... (2 Replies)
Discussion started by: kenshinhimura
2 Replies
2. UNIX for Beginners Questions & Answers
Hi Gurus,
Is there a way to call a variable inside a function anywhere within the script?
Thanks.
BR,
Ernesto (2 Replies)
Discussion started by: ernesto
2 Replies
3. Shell Programming and Scripting
how can i declare variable in perl.
for BLOCK in /sys/block/emcpow* (3 Replies)
Discussion started by: learnbash
3 Replies
4. Shell Programming and Scripting
I am trying to declare a variable like this
#!/bin/csh -f
set c_arg = $a $b $c
However, since i need it to declare before declaring $a ,$b or $c.
As of now i am getting an error which says $a not defined.
Is it possible to define a variable c_arg w/o interpreting the values $a $b $c (2 Replies)
Discussion started by: animesharma
2 Replies
5. Shell Programming and Scripting
what I'm trying to do is ... need to drop tables w/ names like
ABC_NY_2001
ABC_ORD_2001
ABC_TX_2001
ABC_CL_2001
For this, I want to write a query "DROP TABLE ABC_var_2001".
now "var" should be either NY, ORD, TX or CL.
I'm new to programming so don't know how to create a variable w/ OR... (3 Replies)
Discussion started by: ramsowji
3 Replies
6. UNIX for Dummies Questions & Answers
hi to all,
i am trying to declare a variable as an integer in unix shell script. i search the web for a way to do it but it doesnt work.
i tried "define -i" and "declare" but that doesnt work.
if somebody knows another way to declare a variable as integer please help me.
thank you (2 Replies)
Discussion started by: omonoiatis9
2 Replies
7. Shell Programming and Scripting
I recently installed Cygwin on my windows vista to practice on Linux\unix commands.
I am unable to do a simple task of declaring variables on the command prompt
I am trying:
$ vech=Bus
$ echo $vech
bash: vech : command not found
What am I missing? Do i need to add something to .bashrc?
... (1 Reply)
Discussion started by: erora
1 Replies
8. Shell Programming and Scripting
Hi
I have the following script :
#!/bin/ksh
compare()
{
cat $1>t1
cat $2>t2
cy1=`cut -f13 -d'Ç' t1`
cy2=`cut -f13 -d'Ç' t2`
print "cy1 = $cy1"
print "cy2 = $cy2"
if
then
echo "yes"
else
echo "no"
fi
} (6 Replies)
Discussion started by: bittoo
6 Replies
9. Programming
i have created a script to insert 100K rows into mysql db.
But the forst line where i declare the variable is giving error. I am new to mysql. Can anyone help me in this?
the script is
======================================
DECLARE
c INT(10) := 54;
BEGIN
WHILE c <... (4 Replies)
Discussion started by: amitranjansahu
4 Replies
10. Shell Programming and Scripting
Hi frind,
i="1"
while
do
echo "i is $i"
data_file=$HYP_ROOT/import/efcextr$i.txt
echo "$data_file"
i=`expr $i + 1`
done
This is woring finly in ksh but not in ksh.
in ksh it showing error
i=1: Command not found
i: Undefined variable
Kindly help me ...why it is showing the error... (1 Reply)
Discussion started by: deep_kol
1 Replies