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Extract word using sed

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# 1  
Old 03-05-2010
Extract word using sed
Hello,
I am new to sed and am trying to extract a word using sed.

for example i have a line "const TotalAmount& getTotalAmount() const; " in the file test.txt

I am trying to extract getTotalAmount() from the line.

For this i tried
Code:
cat test.txt | sed -n 's/.*get[a-zA-Z]*\(\)//p

But the output is
Code:
       () const;

Could you please let me know the correct expression or what i am doing wrong.

Also could you please suggest some good basic tutorials for Sed.
Last edited by Franklin52; 03-05-2010 at 05:38 AM.. Reason: Please use code tags!
# 2  
Old 03-05-2010
For extracting the getTotalAmount() from the string.You use the following command.

Code:
sed -r 's/.*(get[a-zA-Z]+\(\)).*/\1/g' <file>

This is the best tutorial for reading about SED.

SED and Regular Expressions
Last edited by vivekraj; 03-05-2010 at 05:42 AM..
# 3  
Old 03-05-2010
You try this.

Code:
echo "const TotalAmount& getTotalAmount() const;" | sed -r 's/.{19}//;s/.{7}$//'

Last edited by thillai_selvan; 03-05-2010 at 05:45 AM..
# 4  
Old 03-05-2010
Code:
sed -r "s/.*(getTotalAmount\(\)).*/\1/g" file

# 5  
Old 03-05-2010
MySQL Solution
Try this
Code:
 cat test | sed -nr 's/.*(get[a-zA-Z]*\(\)).*/\1/p'

Output
Code:
getTotalAmount()

I believe that this tutorial would be nice for beginners
Sed - An Introduction and Tutorial
# 6  
Old 03-05-2010
Or you can try this also
Code:
sed -re 's/.{19}//;s/.{8}$//' test.txt

Here what I am doing is I am removing the first 19 characters and last 8 characters.
So you can easily get the middle remaining string as "getTotalAmount()".
# 7  
Old 03-05-2010
Code:
sed -n "s/.*\(get[a-zA-Z]*()\).*/\1/p" infile

Code:
grep -o "get[a-zA-Z]*()" infile

Last edited by Scrutinizer; 03-05-2010 at 06:40 AM.. Reason: You're right. That should be get[a-zA-Z]*() of course (pasto)
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