To Get 1st record from 1st file from list of files


 
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# 1  
Old 02-12-2010
To Get 1st record from 1st file from list of files

Hi

I am trying this cmd and getting

1st file path from list of files(abc2020.txt, abc1010.txt,abc3030.txt):

ls /grid/abc*.txt | head -1

Result for above cmd:

/grid/abc1010.txt

From the this file /grid/abc1010.txt, I need to get 1st record on it.

Data in the file will look like below

10,20,vddd,ee
20,30,gggg,yy

Please help me to solve this as it is crucial to me.
# 2  
Old 02-12-2010
Code:
read RECORD < /grid/abc1010.txt

echo "The first record in /grid/abc1010.txt is '${RECORD}'"

# 3  
Old 02-12-2010
Code:
head -1 `ls /grid/abc*.txt | head -1`

This User Gave Thanks to Vi-Curious For This Post:
# 4  
Old 02-12-2010
Thank you very much. I will try it.
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