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Define Positional Parameter Range Awk

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# 1  
Old 02-02-2010
Define Positional Parameter Range Awk
Hello All,
I am trying to clean up a poorly looking awk command. I am searching for a way to define a range of positional parameters. I may not be searching for the correct syntax.

Example:

Code:
awk ' /14:3*/  {print $2,$3,$4,$5,$6,$7,$8,$9,$10,$11,$12,$13}' app.log

Is it possible to shorten with a range of some kind:

Code:
awk ' /14:3*/  {print $2........$13}' app.log

Thanks for your time.

Jaysunn
Last edited by jaysunn; 02-02-2010 at 10:58 AM.. Reason: Fixed command error.
# 2  
Old 02-02-2010
you can use loop.
Code:
awk '/14:3*/{for (i=2;i<=13;i++){printf "%s ",i}}END{print "\n"}' app.log

# 3  
Old 02-02-2010
This gives me:
Code:
[root@server jason]# awk '/14:3*/{for (i=2;i<=13;i++){printf "%s ",i}}END{print "\n"}' app.log 
2 3 4 5 6 7 8 9 10 11 12 13 2 3 4 5 6 7 8 9 10 11 12 13 2 3 4 5 6 7 8 9 10 11 12 13 2 3 4 5 6 7 8 9 10 11 12 13

How do I specify the positions? I assumed it needs $n.

Thanks for your reply.

Jaysunn
# 4  
Old 02-02-2010
Sorry, It should be

Code:
awk '/14:3*/{for (i=2;i<=13;i++){printf "%s ",$i}}END{print "\n"}' app.log

# 5  
Old 02-02-2010
Code:
awk '/14:3*/{for (i=x-1;i++<y;){printf $i ((i<y)?FS:RS)}}' x=2 y=13

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