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Basic script question

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# 1  
Old 01-20-2010
Basic script question
I'm trying to approach a problem but all I'm coming up with are complex ways to manipulate the data. But still not getting the desired outcome.

directory of files....

file-100-foo
file-100-man
file-100-chu

Need to copy the files and increment the number in the file name

file-101-foo
file-101-man
file-101-chu

Should be easy right? Smilie
# 2  
Old 01-20-2010
something like this (this is all pseudo so yeah don't take it exactly to be literal)

mv $filename `echo "$filename"|sed 's/100/101/g'`

I believe something like that should work for you. If you need it to increment do something like:

for k in `seq 102 200`; do cp $filename `echo "$filename"|sed 's/100/'$k'/g'`; done
# 3  
Old 01-20-2010
Quote:
ls file* | awk -F"-" -v OFS="-" ' { fl=$0; $2++; print "cp " fl " " $0 } ' | ksh
# 4  
Old 01-21-2010
mv $filename `echo "$filename"|sed 's/100/101/g'`

Where does $filename come from?

I tried - ls /dir | grep file > file-list1

that gets me a list of the files, but I'm not sure how to load each one into a cp statement and also sed replace 100 with 101.
# 5  
Old 01-21-2010
Quote:
Originally Posted by suphawk
mv $filename `echo "$filename"|sed 's/100/101/g'`

Where does $filename come from?

I tried - ls /dir | grep file > file-list1

that gets me a list of the files, but I'm not sure how to load each one into a cp statement and also sed replace 100 with 101.
Filename is an environmental variable, you can assign it doing something like

filename="ls ${HOME}/dir"

echo `$filename`
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