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Take each number in table row and find the difference from the corresponding line

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# 1  
Old 01-10-2010
Take each number in table row and find the difference from the corresponding line
I have a two files containing numbers like below. First one contains one number on each line, the other is a table of numbers, each separated by a space. There are the same number of lines in each file.

I want to take each number in the row of the table and find the difference from the corresponding line of the first list. So each value in the row is subtracted from the value in the list at the corresponding line number using awk.

For example

Code:
5
6
7
8
9

Code:
1 2 3 4 5
5 4 3 2 1
1 2 3 4 5
1 2 3 4 5
5 4 3 2 1

Result should be

Code:
-4 -3 -2 -1 0
-1 -2 -3 -4 -5
-6 -5 -4 -3 -2
-7 -6 -5 -4 -3
-4 -5 -6 -7 -8


Actual files will be something like below

Code:
0.4117983
0.4735530
0.6167929
0.7095670
0.7897300
0.8662801
0.9425200
1.020120
1.099846
1.181320
1.263659
1.347084
1.431774
1.520824
1.610451
1.701591
1.793289
1.882924
1.969465

Code:
0.403564 0.403564 0.403564 0.403564 0.403564
0.464079 0.464079 0.464079 0.464079 0.464079
0.604454 0.604454 0.604454 0.604454 0.604454
0.695379 0.695379 0.695379 0.695379 0.695379
0.773935 0.773935 0.773935 0.773935 0.773935
0.848954 0.848954 0.848954 0.848954 0.848954
0.923670 0.923670 0.923670 0.923670 0.923670
0.999718 0.999718 0.999718 0.999718 0.999718
1.077850 1.077850 1.077850 1.077850 1.077850
1.157690 1.157690 1.157690 1.157690 1.157690
1.238390 1.238390 1.238390 1.238390 1.238390
1.320140 1.320140 1.320140 1.320140 1.320140
1.403130 1.403130 1.403130 1.403130 1.403130
1.520820 1.520820 1.520820 1.520820 1.520820
1.642660 1.642660 1.642660 1.642660 1.642660
1.735620 1.735620 1.735620 1.735620 1.735620
1.829160 1.829160 1.829160 1.829160 1.829160
1.920580 1.920580 1.920580 1.920580 1.920580
2.008860 2.008860 2.008860 2.008860 2.008860

Last edited by kristinu; 01-10-2010 at 10:27 AM..
# 2  
Old 01-10-2010
Quote:
paste -d" " file1 file2 | awk ' { var=$1; for( i=2; i<=NF; ++i ) { $(i-1) = $i - var }; NF=NF-1; print } '
# 3  
Old 01-10-2010
It works great. Thanks buddy. Smilie
# 4  
Old 01-10-2010
awk only Smilie
Code:
awk 'NR==FNR{a[NR]=$0;next}{for(i=0;++i<=NF;){$i=($i-a[FNR])}}1'  file1 file2

# 5  
Old 01-10-2010
It works ok, but there is a feature I never encountered before. What's the purpose of the 1 at the end. Without it does not work when I redirect the output to a file. So it must be quite important!!!
# 6  
Old 01-10-2010
Quote:
brksvx58# cat file
0.4117983
0.4735530
0.6167929
brksvx58# awk ' { print } ' file
0.4117983
0.4735530
0.6167929
brksvx58# awk ' 1 ' file
0.4117983
0.4735530
0.6167929
1 means true equivalent to { print }
# 7  
Old 01-10-2010
Oh. Ok, I get it!!!
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