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How to compare a parameter to a string

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# 8  
Old 01-09-2010
The fact that it was 0 is suspicious. Normally 0 indicates that a command was run successfully. Without seeing your code it's hard to tell but it leads me to wonder if somehow $parameter was reassigned by the result of a previous execution. It's just my guess though.
# 9  
Old 01-09-2010
ok, I tried a little test, and I discovered that it changes parameter during the condition of the if. very strange.
Here's the code:

Code:
set parameter = ${3} #${3} is the string
echo "$parameter" #works fine, returns string.
if ($parameter == "string") then
    echo "match: $parameter"
else
    echo "doesn't match: $parameter"
endif

it returns doesn't match: 0
very odd.

# 10  
Old 01-09-2010
It is odd. In fact I tested your script but I was getting a match. I wonder if you would get the same results by using $3 in your conditional instead of assigning it to 'parameter'. It would look like this:

Code:
echo "$3"
if ($3 == "string") then
    echo "match: $3"
else
    echo "doesn't match: $3"
endif

# 11  
Old 01-09-2010
2pugs,

It worked, thanks so much, you're the best. Smilie

Shira.
# 12  
Old 01-09-2010
Try this
Code:
set parameter = ${3} #${3} is the string
echo "$parameter" #works fine, returns string.
if ("$parameter" == "string") then
    echo "match: $parameter"
else
    echo "doesn't match: $parameter"
endif

# 13  
Old 01-09-2010
Hi frans,

I tried this solution, but it didn't work for me.

Thanks,
Shira.
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