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Extract specific read from a data


 
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# 1  
Old 01-08-2010
Extract specific read from a data

Input file:
Code:
#abc_1
SAASFASFGGDSGDSGDSGSDGSDGSDGSDGSDGSDGSDGDS

Output file:
Code:
FASFGGDSGDS

I just want to print out the read from position 5 until position 15 from the data.

Below is the code that I just try but it is failed to get my desired output:
Code:
grep -v '#' input_file | awk '{print substr($0,5,15)}'

Thanks for any advice.
# 2  
Old 01-08-2010
Code:
 echo "SAASFASFGGDSGDSGDSGSDGSDGSDGSDGSDGSDGSDGDS" | cut -c 5-15

# 3  
Old 01-08-2010
Hi ni2,
Thanks for your suggestion.
But I think it seems like not a good solution by using "echo" and "cut" if I got long list of input data and only extract small portion from it Smilie
# 4  
Old 01-08-2010
Code:
awk '! /^#/ { print substr($1, 5, 11) }' input_file

The third argument to substr, if supplied, is the length, not the end point of the string.
# 5  
Old 01-08-2010
thanks scottn,
your suggestion work nice for my problem.
# 6  
Old 01-08-2010
Quote:
Originally Posted by patrick87
Hi ni2,
Thanks for your suggestion.
But I think it seems like not a good solution by using "echo" and "cut" if I got long list of input data and only extract small portion from it Smilie
You can still use cut for this.

Code:
 
$ cat abc_1
SAASFASFGGDSGDSGDSGSDGSDGSDGSDGSDGSDGSDGDS
SAAASFGGDSGDSGDSGSDGSDGSDGSDGSDGSDGSDGDS
SAAFGGDSGDSGDSGSDGSDGSDGSDGSDGSDGSDGDS
 
$ cut -c 5-15 abc_1
FASFGGDSGDS
SFGGDSGDSGD
GGDSGDSGDSG


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