Shell Programming and Scripting

I need to list all files where 1rst column=ABK and char position 123 to 125=ZBK:

For the first part I can I can do a awk '{$1="ABK";print}' file and for the second a cut -c123-125 file | grep ZBK but this would only work partially..

How can I do this with only one awk command ?

Thanks in advance,

Code:

awk ' $1="ABK" && substr($0,123,1)=="N"  ' file > newfile

Code:

awk '$1 == "ABK" && index($0, "ZBK") == 123' infile

That worked perfectly as I expected thanks a lot for both answers!

I have just one more question: Since I have hundred of files instead of doing your awk command file, I would like to run it to all files (awk command *) and therefore I would also need to list/print all files containing the result of my awk command.

May you help me one more time ?

Thanks once again

hi,
I am the new member, I want to place a question on shell scripting, can you please tell me to options to place my post.

Thanks

Use this:

Code:

awk 'FNR == 1 { c = 0 }
$1 == "ABK" && index($0, "ZBK") == 123 {
  c++ || $0 = FILENAME RS $0; print 
  }' *

Or this:

Code:

awk '$1 == "ABK" && index($0, "ZBK") == 123 { 
  print FILENAME, $0 
  }' *

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I have nothing more to say..., just a BIG BIG THANK YOU radoulov!

Thanks for your great help